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BITSAT 2016

Exam: BITSAT
Year: 2016
Subject: Chemistry
Chapter: States of Matter

BITSAT 2016 · Chemistry · States of Matter

At what temperature, the rate of effusion of N_ 2 would be 1.625...

At what temperature, the rate of effusion of

\mathrm{N}_{2}

would be 1.625 times than that of

\mathrm{SO}_{2}

at

50^{{}^{\circ}} \mathrm{C}

?

Options

A $110 \mathrm{ K}$
B $173 \mathrm{ K}$
C $373 \mathrm{ K}$
D $273 \mathrm{ K}$

Correct answer

C. $373 \mathrm{ K}$

Step-by-step solution

\quad r \propto U

and

U=\sqrt{\frac{3 R T}{\text{ M }}}\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}=\sqrt{\frac{\mathrm{T}_{1} \mathrm{M}_{2}}{\mathrm{ T}_{2} \mathrm{M}_{1}}}

or

\frac{\mathrm{r}_{\mathrm{N}_{2}}}{\mathrm{r}_{\mathrm{SO}_{2}}}=\sqrt{\frac{\mathrm{T}_{1} \times 64}{323 \times 28}}=1.625

or

\mathrm{T}_{2}=373

\mathrm{ K}

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