A photon of wavelength 3000 Ã… strikes a metal surface. The work function of the metal is 2.13 eV. What is the kinetic energy of the emitted photoelectron? ( h =6.626 10⁻³⁴ Js )

Step-by-step solution

=3000 Ã…=3 10⁻⁷ ~m , =2.13 eV K.E. =h v-h v₀=h v- = h c - = (6.626 10⁻³⁴ 3 10^8 ) 3 10⁻⁷ - (2.13 1.6 10⁻¹⁹ )= 1.98 10⁻²⁵ 3 10⁻⁷ - (3.408 10⁻¹⁹ )= (6.60 10⁻¹⁹ )- (3.408 10⁻¹⁹ )=3.192 10⁻¹⁹ ~J =2.0 eV