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BITSAT 2024Paper 1
Exam
BITSAT
Year
2024
Paper
Paper 1
Subject
Chemistry
Chapter
Structure of Atom

BITSAT 2024 · Paper 1 · Chemistry · Structure of Atom

A stream of electrons from a heated filament was passed between two...

A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference VV volt. If 'e' and mm are charge and mass of an electron, respectively, then the value of h/λh / \lambda (where λ\lambda is wavelength associated with electron wave) is given by:

Options

  1. AmeV\sqrt{m \mathrm{e} V}
  2. B2meV\sqrt{2 m \mathrm{e} V}
  3. CmeVm \mathrm{eV}
  4. D2meV2 m \mathrm{e} V

Correct answer

B. 2meV\sqrt{2 m \mathrm{e} V}

Step-by-step solution

As electron of charge ' ee ' is passed through ' VV ' volt, kinetic energy of electron will be eV. Wavelength of electron wave (λ)=h2m⋅KEλ=−h2meV∴hλ=2meV(\lambda)=\frac{h}{\sqrt{2 m \cdot \mathrm{KE}}}\lambda=-\frac{h}{\sqrt{2 m \mathrm{eV}}} \quad \therefore \frac{h}{\lambda}=\sqrt{2 m \mathrm{eV}}
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