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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Chemistry
Chapter
Surface Chemistry

BITSAT 2011 · Chemistry · Surface Chemistry

For adsorption of a gas on a solid, the plot of log x / m vs log P...

For adsorption of a gas on a solid, the plot of log x/mx / m vs log PP is linear with slope equal to (nbeingwholenumber)being whole number)

Options

  1. Akk
  2. Blog⁡k\log k
  3. Cnn
  4. D1n\frac{1}{n}

Correct answer

D. 1n\frac{1}{n}

Step-by-step solution

According to Freundlich adsorption isotherm, at intermediate pressure, extent of adsorption xm=\frac{x}{m}= k P1/n or log⁡xm=log⁡\mathrm{P}^{1 / n} \text{ or } \log \frac{x}{m}=\log k+1nlog⁡Pplotoflog⁡xm\frac{1}{n} \log \mathrm{P} \\ plot of \log \frac{x}{m} vs log P\mathrm{P} is linear with slope =1n=\frac{1}{n}
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