If the angle made by the tangent at the point (x₀, y₀ ) on the curve x=12(t+ t t), y=12(1+ t)^2, 0 t 2 , with the positive x -axis is 3 , then y₀ is equal to

Step-by-step solution

Given equation of curve x=12(t+ t t), y=12(1+ t)^2 Differentiate w.r.t ' t ', aligned & d x d t =12 (1+ ^2 t- ^2 t ) & d x d t =12(1+ 2 t) and d y d t & =24(1+ t) t & d y d x = 2(1+ t) t 1+ 2 t aligned