Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2021MathematicsArea Under CurvesActual

The area bounded by the curves x+2 y²=0 and x+3 y²=1 is

Options

  1. A1 sq. unit
  2. B1 3 sq. units
  3. C2 3 sq. units
  4. D4 3 sq. units

Correct answer

D. 4 3 sq. units

Step-by-step solution

We have, x+2 y²=0 y²=- x 2 (i) a parabola with vertex (0,0) and x+3 y²=1 y²= 1-x 3 =- ( x-1 3 ) (ii), a parabola with vertex (1,0) Solving (i) and (ii), we get y= 1 A = _ -1 ¹ ( (1-3 y² )- (-2 y² ) ) d y=2 ₀¹ (1-y² ) d y=2 [y- y³ 3 ]₀¹= 4 3 sq.units

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

The line y=m x bisects the area unclosed by lines x=0, y=0 and x= 3 2 and the curve y=1+4 x-x^2 . Then, the value of m is 2024If a, c, b are in GP, then the area of the triangle formed by the lines a x+b y+c=0 with the coordinates axes is equal to 2024The area enclosed by the curves y=x^3 and y= x is 2024The area of the region bounded by the curves x=y^2-2 and x=y is 2024If the area bounded by the curves y=a x^2 and x=a y^2,(a 0) is 3 sq units, then the value of a is 2024The area of the region R = (x, y): 5 x^2 y 2 x^2+9 is : 2023The area enclosed between the curve y= _e(x+e) and the coordinate axes is 2023The area of the region bounded by the parabola (y-2)^2=(x-1) , the tangent to the parabola at the point (2,3) and the X -axis is 2022 Full Area Under Curves list All BITSAT PYQs