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Area Under Curves — BITSAT Mathematics PYQs

24 previous year questions from Area Under Curves with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

24 questionsMathematicsSolutions on every page
1

The line y=m x bisects the area unclosed by lines x=0, y=0 and x= 3 2 and the curve y=1+4 x-x^2 . Then, the value of m is

BITSAT 2024 Solution
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2

If a, c, b are in GP, then the area of the triangle formed by the lines a x+b y+c=0 with the coordinates axes is equal to

BITSAT 2024 Solution
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3

The area enclosed by the curves y=x^3 and y= x is

BITSAT 2024 Solution
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4

The area of the region bounded by the curves x=y^2-2 and x=y is

BITSAT 2024 Solution
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5

If the area bounded by the curves y=a x^2 and x=a y^2,(a 0) is 3 sq units, then the value of a is

BITSAT 2024 Solution
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6

The area of the region R = (x, y): 5 x^2 y 2 x^2+9 is :

BITSAT 2023 Solution
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7

The area enclosed between the curve y= _e(x+e) and the coordinate axes is

BITSAT 2023 Solution
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8

The area of the region bounded by the parabola (y-2)^2=(x-1) , the tangent to the parabola at the point (2,3) and the X -axis is

BITSAT 2022 Solution
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9

The area enclosed by the curves y= x+ x and y=| x- x| over the interval [0, 2 ] is

BITSAT 2022 Solution
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10

The area bounded by the curves x+2 y²=0 and x+3 y²=1 is

BITSAT 2021 Solution
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11

The area bounded by curves (x-1)²+y²=1 and x²+y²=1 is

BITSAT 2021 Solution
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12

The line y=m x bisects the area enclosed by lines x=0, y =0 and x =3 / 2 and the curve y =1+4 x - x ² Then the value of m is

BITSAT 2020 Solution
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13

The point ( [ P + 1 ] , [ P ] ) (where, [ x ] is the greatest integer function) lying inside the region bounded by the circle x 2 + y 2 - 2 x - 15 = 0 and x 2 + y 2 - 2 x - 7 = 0 ,

BITSAT 2019 Solution
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14

Area bounded by two branches of the curve y - x 2 = x 3 and x = 1 is

BITSAT 2019 Solution
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15

The area of the region included between the curves x 2 + y 2 = a 2 and x + y = a a > 0 is

BITSAT 2018 Solution
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16

The area under the curve y = cos x - sin x , 0 ≤ x ≤ π 2 and above X -axis, is

BITSAT 2017 Solution
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17

The area enclosed by the curves y = x 3 and y = x is

BITSAT 2017 Solution
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18

A wire 34 ~cm long is to be bent in the form of a quadrilateral of which each angle is 90^ . What is the maximum area which can be enclosed inside the quadrilateral?

BITSAT 2016 Solution
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19

The area of the region R = (x, y):|x| |y| . and x² .+y² 1 is

BITSAT 2015 Solution
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20

The area bounded by the x -axis, the curve y=f(x) and the lines x =1, x = b , is equal to b ²+1 - 2 for all b>1, then f(x) is

BITSAT 2014 Solution
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21

Area intercepted by the curves y= x x [0, ] and y = 2 x , x [0, ], is

BITSAT 2013 Solution
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22

The area bounded by the curve y= x, x -axis and the ordinates x=0 and x= / 2 is

BITSAT 2012 Solution
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23

What is the area bounded by (y= x, y=0 ) and (x= 4 ? )

BITSAT 2011 Solution
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24

If ( I _ m = ₁^ e ( x )^ m dx ), where ( m N ), then (I₁₀+10 I₉ ) is equal to -

BITSAT 2010 Solution
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