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BITSAT Area Under Curves PYQs with Solutions

24 previous year questions from Area Under Curves (BITSAT Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

24 questionsMathematics2010–2024Answers + solutions

About Area Under Curves PYQs

Area Under Curves has 24 previous year questions in the Quantrex Academy BITSAT Mathematics bank. The 24 questions in this list come from BITSAT (24), spanning 2010 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

  • 2024: 5
  • 2023: 2
  • 2022: 2
  • 2021: 2
  • 2020: 1
  • 2019: 2
  • 2018: 1
  • 2017: 2
  • 2016: 1
  • 2015: 1
  • 2014: 1
  • 2013: 1

Area Under Curves questions with solutions

1

The line y=m x bisects the area unclosed by lines x=0, y=0 and x=(3)/(2) and the curve y=1+4 x-x^2 . Then, the value of m is

BITSAT 2024 Solution
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2

If a, c, b are in GP, then the area of the triangle formed by the lines a x+b y+c=0 with the coordinates axes is equal to

BITSAT 2024 Solution
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3

The area enclosed by the curves y=x^3 and y= x is

BITSAT 2024 Solution
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4

The area of the region bounded by the curves x=y^2-2 and x=y is

BITSAT 2024 Solution
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5

If the area bounded by the curves y=a x^2 and x=a y^2,(a>0) is 3 sq units, then the value of a is

BITSAT 2024 Solution
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6

The area of the region R=\ (x, y): 5 x^2 ≤ y ≤ 2 x^2+9\ is :

BITSAT 2023 Solution
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7

The area enclosed between the curve y= _e(x+e) and the coordinate axes is

BITSAT 2023 Solution
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8

The area of the region bounded by the parabola (y-2)^2=(x-1) , the tangent to the parabola at the point (2,3) and the X -axis is

BITSAT 2022 Solution
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9

The area enclosed by the curves y= x+ x and y=| x- x| over the interval [0, (π)/(2)] is

BITSAT 2022 Solution
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10

The area bounded by the curves x+2 y^ 2 =0 and x+3 y^ 2 =1 is

BITSAT 2021 Solution
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11

The area bounded by curves (x-1)^ 2 +y^ 2 =1 and x^ 2 +y^ 2 =1 is

BITSAT 2021 Solution
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12

The line y=m x bisects the area enclosed by lines x=0, y=0 and x=3 / 2 and the curve y=1+4 x- ^ 2 Then the value of m is

BITSAT 2020 Solution
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13

The point ( [ P + 1 ] , [ P ] ) (where, [ x ] is the greatest integer function) lying inside the region bounded by the circle x^ 2 + y^ 2 - 2x - 15 = 0 and x^ 2 + y^ 2 - 2x - 7 =

BITSAT 2019 Solution
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14

Area bounded by two branches of the curve (y - x)2 = x^ 3 and x = 1 is

BITSAT 2019 Solution
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15

The area of the region included between the curves x ^ 2 + y ^ 2 = a ^ 2 and |x| + |y| = a (a > 0) is

BITSAT 2018 Solution
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16

The area under the curve y = |cosx - sinx|, 0 ≤ x ≤ (π)/(2) and above X -axis, is

BITSAT 2017 Solution
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17

The area enclosed by the curves y = x^ 3 and y = x is

BITSAT 2017 Solution
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18

A wire 34 cm long is to be bent in the form of a quadrilateral of which each angle is 90^ ^ ∘ . What is the maximum area which can be enclosed inside the quadrilateral?

BITSAT 2016 Solution
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19

The area of the region R=\ (x, y):|x| ≤|y|. and x^ 2 .+y^ 2 ≤ 1\ is

BITSAT 2015 Solution
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20

The area bounded by the x -axis, the curve y=f(x) and the lines x=1, x=b, is equal to ^ 2 +1 - 2 for all b > 1, then f(x) is

BITSAT 2014 Solution
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21

Area intercepted by the curves y= xx ∈[0, π] and y= 2 x, x ∈[0, π], is

BITSAT 2013 Solution
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22

The area bounded by the curve y= x, x -axis and the ordinates x=0 and x=π / 2 is

BITSAT 2012 Solution
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23

What is the area bounded by \(y= x, y=0\) and \(x= (π)/(4) ?\)

BITSAT 2011 Solution
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24

If \( I_ m =∫_ 1^ e ( x)^ m dx \), where \( m ∈ N \), then \(I_ 10 +10 I_9\) is equal to -

BITSAT 2010 Solution
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