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BITSAT2016MathematicsArea Under CurvesActual

A wire 34 ~cm long is to be bent in the form of a quadrilateral of which each angle is 90^ . What is the maximum area which can be enclosed inside the quadrilateral?

Options

  1. A68 ~cm ²
  2. B70 ~cm ²
  3. C71.25 ~cm ²
  4. D72.25 ~cm ²

Correct answer

D. 72.25 ~cm ²

Step-by-step solution

Let one side of quadrilateral be x and another side be y so, 2(x+y)=34 or (x+y)=17 We know from the basic principle that for a given perimeter square has the maximum area, so , x = y and putting this value in equation (i) x = y = 17 2 Area =x y= 17 2 17 2 = 289 4 =72.25

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