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BITSAT 2021
Exam
BITSAT
Year
2021
Subject
Mathematics
Chapter
Functions

BITSAT 2021 · Mathematics · Functions

The domain of the function f(x)= 1 x^ 12 -x^ 9 +x^ 4 -x+1 is given...

The domain of the function f(x)=1x12−x9+x4−x+1\mathrm{f}(x)=\frac{1}{\sqrt{x^{12}-x^{9}+x^{4}-x+1}} is given by

Options

  1. A(−∞,−1)(-\infty,-1)
  2. B(1,∞)(1, \infty)
  3. C(−1,1)(-1,1)
  4. D(−∞,∞)(-\infty, \infty)

Correct answer

D. (−∞,∞)(-\infty, \infty)

Step-by-step solution

f(x)\mathrm{f}(x) is defined for x12−x9+x4−x+1>0x^{12}-x^{9}+x^{4}-x+1 > 0⇒x4(x8+1)−x(x8+1)+1>0⇒(x8+1)x(x3−1)+1>0\begin{array}{l} \Rightarrow x^{4}\left(x^{8}+1\right)-x\left(x^{8}+1\right)+1 > 0 \\ \Rightarrow\left(x^{8}+1\right) x\left(x^{3}-1\right)+1 > 0 \end{array}If $x \geq 1$ or $x \leq-1$, then the above expres - sion is positive. If $-1 < x \leq 0$, the above inequality still holds. If 0 < x < 1$, then\begin{array}{l} x^{12}-x\left(x^{8}+\right)+\left(x^{4}+1\right)>0 \\ \because\left[x^{4}+1>x^{8}+1 \text{ and so } x^{4}+1>x\left(x^{8}+1\right)\right] \end{array}$$ThedomainofThe domain of f=(-\infty, \infty)$
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