ABC is a triangular park with AB = AC =100 ~m . A TV tower stands at the mid-point of BC . The angles of elevation of the top of the tower at A, B, C are 45^ , 60^ , 60^ respectively. The height of the tower is

Step-by-step solution

45^ = PQ AQ = h AQ h = AQ Where PQ is tower and ABC is the park, with Q being mid point of the side BC and PQ = h Also, A Q²+B Q²=100² h ²+ h ² ² 60^ =100² h ² [1+ 1 3 ]=100² h ²= 3 100² 4 h =50 3