Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Mathematics
Chapter
Heights and Distances

BITSAT 2011 · Mathematics · Heights and Distances

A ladder rests against a wall so that its top touches the roof of...

A ladder rests against a wall so that its top touches the roof of the house. If the ladder makes an angle of (60^{{}^{\circ}}) with the horizontal and height of the house be (6 3\sqrt{3}) meters, then the length of the ladder in meters is

Options

  1. A(12 3\sqrt{3})
  2. B12
  3. C(12 / 3\sqrt{3})
  4. DNone of these

Correct answer

B. 12

Step-by-step solution

Length of ladder (=63sin⁡60∘=\frac{6 \sqrt{3}}{\sin 60^{{}^{\circ}}}=12  m\mathrm{~m})
Practice Heights and Distances on Quantrex Academy →

More from Heights and Distances

From the top of a cliff 50 m high, the angles of depression of the top and bottom of a… BITSAT 2024A B C is a triangular park with A B=A C=100 m . A TV tower stands at the mid-point of B C… BITSAT 2024Let α be the solution of 16^ ^2 θ +16^ ^2 θ =10 in (0, (π)/(4)) . If the shadow of a… BITSAT 2022A house subtends a right angle at the window of a opposite house and the angle of… BITSAT 2022ABC is a triangular park with AB=AC=100 m. A TV tower stands at the mid-point of BC . The… BITSAT 2020In a triangle ABC, ∠ C=90^ ∘ , then (a^2-b^2)/(a^2+b^2) is equal to : BITSAT 2009 Full Heights and Distances list Heights and Distances JEE Maths PYQsJEE Mathematics PYQs All BITSAT PYQs