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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Mathematics
Chapter
Matrices

BITSAT 2011 · Mathematics · Matrices

If (A= [ array lll 2 & 0 & 0 2 & 2 & 0 2 & 2 & 2 array ]), then...

If (A=\left[200220222\begin{array}{lll}2 & 0 & 0 \\ 2 & 2 & 0 \\ 2 & 2 & 2\end{array}\right]), then (\operatorname{adj}(\operatorname{adj} A)) is equal to -

Options

  1. A(8\left[100110111\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}$\right])
  2. B(16\left[100110111\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}$\right])
  3. C(64\left[100110111\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}$\right])
  4. DNone of these

Correct answer

B. (16\left[100110111\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}$\right])

Step-by-step solution

(|A|=\left[200220222\begin{array}{lll}2 & 0 & 0 \\ 2 & 2 & 0 \\ 2 & 2 & 2 \end{array}\right]=(2)(2)(2)=8) Now adj ((\operatorname{adj} A)=|\mathrm{A}|^{3-2}  A\mathrm{~A} (=8 \left[200220222\begin{array}{lll}2 & 0 & 0 \\ 2 & 2 & 0 \\ 2 & 2 & 2 \end{array}\right]=16 \left[100110111\begin{array}{ccc}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1 \end{array}$\right])
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