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Matrices — BITSAT Mathematics PYQs

19 previous year questions from Matrices with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

19 questionsMathematicsSolutions on every page
1

If A= 1 3 [ array ccc 1 & 2 & 2 2 & 1 & -2 a & 2 & b array ] is an orthogonal matrix, then

BITSAT 2024 Solution
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2

If matrix A= [ array ccc 3 & -2 & 4 1 & 2 & -1 0 & 1 & 1 array ] and A⁻¹= 1 k adj (A) , then k is

BITSAT 2024 Solution
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3

If A and B are symmetric matrices of same order such that A B+B A=X and A B-B A=Y , then (X Y)^ T =

BITSAT 2024 Solution
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4

If A= [ array cc 1 & 0 0 & -1 array ], P= [ array ll 1 & 1 0 & 1 array ] and X=A P A^T , then A^T X⁵⁰ A=

BITSAT 2024 Solution
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5

If A is a square matrix of order 3 , then Adj ( Adj .A^2 ) =

BITSAT 2024 Solution
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6

If A= [ array ccc 0 & c & -b -c & 0 & a b & -a & 0 array ] and B= [ array ccc a^2 & a b & a c a b & b^2 & b c a c & b c & c^2 array ] , then A B is equal to

BITSAT 2023 Solution
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7

If A = [ array cc 0 & 2 3 & -4 array ] and k ~A = [ array cc 0 & 3 a 2 b & 24 array ] , then the values of k, a and b respectively are:

BITSAT 2023 Solution
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8

Let A= [ array ccc 1 & -1 & 1 2 & 1 & -3 1 & 1 & 1 array ] and 10 B= [ array ccc 4 & 2 & 2 -5 & 0 & 1 & -2 & 3 array ] If B is the inverse of A , then the value of is

BITSAT 2022 Solution
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9

If [ array cc 1 & - & 1 array ] [ array cc 1 & - & 1 array ]⁻¹= [ array cc a & -b b & a array ], then

BITSAT 2022 Solution
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10

If A is an 3 × 3 non- singular matrix, such that A A ' = A ' A and B = A - 1 A ' , then B B ' equals to

BITSAT 2019 Solution
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11

If P = a b c b c a c a b , a b c = 1 , P T P = I then the value of a 3 + b 3 + c 3 is

BITSAT 2018 Solution
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12

Let M bea 3 3 n n -singular matrix with det ( M )= . If [ M ⁻¹ . adj ( adj ( M )]= KI , then the value of K is

BITSAT 2015 Solution
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13

If [ array cc & & - array ] is square root of identity matrix of order 2 then -

BITSAT 2014 Solution
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14

If A = [ array ll 1 & 1 1 & 1 array ] then A ¹⁰⁰ :

BITSAT 2014 Solution
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15

Let A= [ array ll 0 & 0 & 0 array ] and (A+I)⁵⁰-50 A= [ array ll a & b c & d array ] , find a b c+a b d+b c d+a c d

BITSAT 2012 Solution
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16

The matrix (A^2+4 A-5 I ), where (I ) is identity matrix and (A= [ array cc 1 & 2 4 & -3 array ] ), equals :

BITSAT 2011 Solution
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17

If (A= [ array lll 2 & 0 & 0 2 & 2 & 0 2 & 2 & 2 array ] ), then ( adj ( adj A) ) is equal to -

BITSAT 2011 Solution
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18

The value of ( ⁻¹ x+ ⁻¹ ( x 2 + 1 2 3-3 x^2 ) ); ( 1 2 x 1 ) is

BITSAT 2010 Solution
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19

Find the value of (2 ⁻¹ 1 5 + ⁻¹ 1 2 +2 ⁻¹ 1 8 )

BITSAT 2009 Solution
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