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BITSAT 2023Paper 1
Exam
BITSAT
Year
2023
Paper
Paper 1
Subject
Mathematics
Chapter
Statistics

BITSAT 2023 · Paper 1 · Mathematics · Statistics

Find the mean deviation about the mean for the data...

Find the mean deviation about the mean for the data 4,7,8,9,10,12,13,174,7,8,9,10,12,13,17

Options

  1. A3
  2. B24
  3. C10
  4. D8

Correct answer

A. 3

Step-by-step solution

Arithmetic mean xˉ\bar{x} of 4,7,8,9,10,12,134,7,8,9,10,12,13, 17 isxˉ=4+7+8+9+10+12+13+178=808=10Σ∣xi−xˉ∣=6+3+2+1+0+2+3+7=24∴\bar{x}=\frac{4+7+8+9+10+12+13+17}{8}=\frac{80}{8}=10 \Sigma\left|x_i-\bar{x}\right|=6+3+2+1+0+2+3+7=24 \therefore Mean deviation about mean= M.D. (xˉ)=∑∣xi−xˉ∣n=248=3=\text{ M.D. }(\bar{x})=\frac{\sum\left|x_i-\bar{x}\right|}{n}=\frac{24}{8}=3
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