BITSAT 2018
- Exam
- BITSAT
- Year
- 2018
- Subject
- Mathematics
- Chapter
- Straight Lines
BITSAT 2018 · Mathematics · Straight Lines
OPQR is a square and M, N are the middle points of the sides PQ and...
is a square and are the middle points of the sides and respectively, then the ratio of the areas of the square and is

Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Taking the coordinates of vertices as ,~respectively.
The coordinates of is \left(a, \dfrac{a}{2}\right)

~Area of& \Delta OMN = \dfrac{1}{2}\left|\begin{cases}0 & 0 & 1 \\ a & a / 2 & 1 \\ a / 2 & a & 1\end{cases}\right| = \dfrac{3a^{2}}{8}
and area of the square
The required ratio is .
Hence, option (c) is correct.