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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Mathematics
Chapter
Straight Lines

BITSAT 2018 · Mathematics · Straight Lines

OPQR is a square and M, N are the middle points of the sides PQ and...

OPQROPQR is a square and M,NM, N are the middle points of the sides PQPQ and QRQR respectively, then the ratio of the areas of the square and ΔOMN\Delta OMN isOPQR is a square and M, N are the middle points of the sides PQ and QR respectively, then the ratio of the areas of the

Options

  1. A4:14: 1
  2. B2:12: 1
  3. C8:38: 3
  4. D4:34: 3

Correct answer

C. 8:38: 3

Step-by-step solution

Taking the coordinates of vertices O,P,Q,RO, P, Q, R as (0,0),(a,0),(a,a),(0,a)( 0, 0 ) , ( a, 0 ) , ( a, a ) , ( 0, a ),~respectively.

∴∴ The coordinates of MM is \left(a, \dfrac{a}{2}\right)andNis(a2,a)and N is \left(\dfrac{a}{2}, a\right)

OPQR is a square and M, N are the middle points of the sides PQ and QR respectively, then the ratio of the areas of the

∴∴~Area of& \Delta OMN = \dfrac{1}{2}\left|\begin{cases}0 & 0 & 1 \\ a & a / 2 & 1 \\ a / 2 & a & 1\end{cases}\right| = \dfrac{3a^{2}}{8}

and area of the square =a2= a^{2}

∴∴ The required ratio is 8:38: 3.

Hence, option (c) is correct.

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