BITSAT2024MathematicsThree Dimensional GeometryActual
The angle between the lines whose direction cosines are given by the equations 3 l+m+5 n=0,6 ~nm -2 n l+5 l m =0 is
Options
- A⁻¹ ( 1 6 )
- B⁻¹ (- 1 6 )
- C⁻¹ ( 2 3 )
- D⁻¹ (- 5 6 )
Correct answer
B. ⁻¹ (- 1 6 )
Step-by-step solution
The given equations are 3 l+m+5 n=0 ...(i) and 6 mn -2 n l+5 l m =0 ...(ii) From (i), we have m=-3 l-5 n . Putting m =-3 l-5 n in (ii), we get 6(-3 l-5 n) n-2 n l+5 l(-3 l-5 n)=0 (n+l)(2 n+l)=0 either l=- n or l=-2 n . If l=-n , then putting l=-n in (i), we obtain m=-2 n . If l=-2 n , then putting l=-2 n in (i), we obtain m = n . Thus, the direction ratios of two lines are - n ,-2 n , n and -2 n , n , n i.e., 1,2,-1 and -2,1,1 . Hence, the direction cosines are 1 6 , 2 6 , -1 6 or -2 6 , 1 6 , 1 6 . The angle betwe