BITSAT2024MathematicsThree Dimensional GeometryActual
Let the acute angle bisector of the two planes x-2 y-2 z+1=0 and 2 x-3 y-6 z+1=0 be the plane P . Then which of the following points lies on P?
Options
- A(3,1,- 1 2 )
- B(-2,0,- 1 2 )
- C(0,2,-4)
- D(4,0,-2)
Correct answer
B. (-2,0,- 1 2 )
Step-by-step solution
Given that P₁: x-2 y-2 z+1=0P₂: 2 x-3 y-6 z+1=0 Equation of plane bisectors aligned & | x-2 y-2 z+1 1+4+4 |= | 2 x-3 y-6 z+1 2^2+3^2+6^2 | & x-2 y-2 z+1 3 = 2 x-3 y-6 z+1 7 aligned Since a ₁ a ₂+ b ₁ ~b ₂+ c ₁ c ₂=20 0 Negative sign will be taken for acute bisector. aligned & 7 x-14 y-14 z+7=-[6 x-9 y-18 z+3] & 13 x-23 y-32 z+10=0 & (-2,0,- 1 2 ) satisfy it aligned