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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Mathematics
Chapter
Vector Algebra

BITSAT 2012 · Mathematics · Vector Algebra

If a .b =a .c and a × b=a × c , then correct statement is

If aa.b =a=a.c and a×b=a×ca \times b=a \times c, then correct statement is

Options

  1. Aa∥(b−c)\mathrm{a} \|(\mathrm{b}-\mathrm{c})
  2. Ba⊥(b−c)a \perp(b-c)
  3. Ca=0a=0 or b=cb=c
  4. DNone of these

Correct answer

C. a=0a=0 or b=cb=c

Step-by-step solution

a.b.=a⋅c⇒a⋅(b−c)=0⇒a=0orb−c=0a. b.=a \cdot c \Rightarrow a \cdot(b-c)=0\Rightarrow \mathrm{a}=0 \mathrm{or} \mathrm{b}-\mathrm{c}=0 or a⊥(b−c)⇒a=0\mathrm{a} \perp(\mathrm{b}-\mathrm{c})\Rightarrow \mathrm{a}=0 or b=c\mathrm{b}=\mathrm{c} or a⊥(b−c)\mathrm{a} \perp(\mathrm{b}-\mathrm{c}) Also a xb=axc⇒a×(b−c)=0⇒a=0x b=a x c \Rightarrow a \times(b-c)=0\Rightarrow \mathrm{a}=0 or b−c=0\mathrm{b}-\mathrm{c}=0 or a ∥(b−c)⇒a=0\|(\mathrm{b}-\mathrm{c})\Rightarrow a=0 or b=cb=c or a∥(b−c)a \|(b-c) Observing to ( 1 ) and ( 2 ) we find that a=0\mathrm{a}=0 or b=c\mathrm{b}=\mathrm{c}
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