The ratio of the shortest wavelength of Balmer series to the...

Wavelength of H -atom is $\frac{1}{\lambda}=\mathrm{Rz}^2$\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) Shortest wavelength for Balmer series: \frac{1}{\lambda_B}=\mathrm{Rz}^2 \left(\frac{1}{2^2}-\frac{1}{\infty}\right)$Shortest wavelength for Lyman series:$\frac{1}{\lambda_{\mathrm{L}}}=\mathrm{Rz}^2 \left(\frac{1}{1^2}-\frac{1}{\infty}\right) ....(ii) Dividing eq. (i) and (ii), $\lambda_{\mathrm{A}}$: \lambda_1=4: 1