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BITSAT 2024Paper 1
Exam
BITSAT
Year
2024
Paper
Paper 1
Subject
Physics
Chapter
Atomic Physics

BITSAT 2024 · Paper 1 · Physics · Atomic Physics

The minimum excitation energy of an electron revolving in the first...

The minimum excitation energy of an electron revolving in the first orbit of hydrogen is

Options

  1. A3.4 eV
  2. B8.5 eV
  3. C10.2 eV
  4. D13.6 eV

Correct answer

C. 10.2 eV

Step-by-step solution

Energy of electron in nth \mathrm{n}^{\text{th }} orbit En=−13.6eVn2E_n=\frac{-13.6 e V}{n^2} Excitation energy of electron from n=1n=1 to n=2E=−13.6[122−11]=−13.6[14−11]=10.2n=2E=-13.6\left[\frac{1}{2^2}-\frac{1}{1}\right]=-13.6\left[\frac{1}{4}-\frac{1}{1}\right]=10.2eV\mathrm{eV}
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