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BITSAT2021PhysicsCenter of Mass, Momentum and CollisionActual

Three bricks each of length L and mass M are arranged as shown from the wall. The distance of the centre of mass of the system from the wall is

Options

  1. AL 4
  2. BL 2
  3. C( 3 2 ) L
  4. D( 11 12 ) L

Correct answer

D. ( 11 12 ) L

Step-by-step solution

x₁= L 2 , x₂= L , x₃= 5 ~L 4 x_ CM = m₁ x₁+m₂ x₂+m₃ x₃ m₁+m₂+m₃ = M L 2 + M L + M 5 ~L 4 M + M + M = 11 ~L 12

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