An object of mass 5 kg is projected with a velocity 20 m s - 1 at an angle 60 ° , to the horizontal. At the highest point of its path, the projectile explodes and breaks up into two fragments of masses 1 kg and 4 kg . The fragments separate horizontally after the explosion, which releases internal energy such that the K E of the system af the highest point is doubled. The separation between the two fragments whe

Step-by-step solution

Given, m = 5   kg , v = 20   m   s - 1 , θ = 60 ° Vertical component of velocity, v y = v   sin   60 ° = 20 × 3 2 = 10 3   m   s - 1 Time taken to reach the highest point = Time taken to reach the ground from highest point. t = v   sin   θ g = v y g = 10 3 9 . 8 = 1 . 77   s At the highest point, m splits up into two parts of masses m 1 = 1   kg and m 2 = 4   kg If their velocities are v 1 and v 2 respectively, then applying the pr