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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Dual Nature of Matter

BITSAT 2024 · Paper 2 · Physics · Dual Nature of Matter

The acceptor level of a p-type semiconductor is 6 eV. The maximum...

The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be : Given hc =1242eV=1242 \mathrm{eV} nm.

Options

  1. A407 nm
  2. B414 nm
  3. C207 nm
  4. D103.5 nm

Correct answer

C. 207 nm

Step-by-step solution

Energy is, E=hcλE=1242nm−eVλ⇒λ=12426=207nm\mathrm{E}=\frac{\mathrm{hc}}{\lambda}\mathrm{E}=\frac{1242 \mathrm{ nm}-\mathrm{eV}}{\lambda} \Rightarrow \lambda=\frac{1242}{6}=207 \mathrm{ nm}
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