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BITSAT2024PhysicsDual Nature of MatterActual

The acceptor level of a p-type semiconductor is 6 eV . The maximum wavelength of light which can create a hole would be : Given hc =1242 eV nm .

Options

  1. A407 nm
  2. B414 nm
  3. C207 nm
  4. D103.5 nm

Correct answer

C. 207 nm

Step-by-step solution

Energy is, E = hc E = 1242 ~nm - eV = 1242 6 =207 ~nm

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