BITSAT2024PhysicsElectromagnetic WavesActual
A parallel plate capacitor consists of two circular plates of radius R=0.1 ~m . They are separated by a short distance. If electric field between the capacitor plates changes as d E d t =6 10¹³ ~V ~m s , then the value of displacement current is
Options
- A15.25 A
- B6.25 A
- C16.67 A
- D4.69 A
Correct answer
C. 16.67 A
Step-by-step solution
Given, area of plates, A= R^2=3.14 (0.1)^2 ~m ^2 and d E d t =6 10¹³ ~V ~m s Displacement current between the plates, aligned I_d & = ₀ d d t I_d & = ₀ A ( d E d t ) [ d d t =A d E d t ] & =8.85 10⁻¹² 3.14 (0.1)^2 6 10¹³ I_d & =16.67 ~A aligned