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BITSAT 2023Paper 1

Exam: BITSAT
Year: 2023
Paper: Paper 1
Subject: Physics
Chapter: Electromagnetic Waves

BITSAT 2023 · Paper 1 · Physics · Electromagnetic Waves

The ratio of average electric energy density and total average...

The ratio of average electric energy density and total average energy density of electromagnetic wave is :

Options

A2
B $\frac{1}{2}$
C1
D3

Correct answer

B. $\frac{1}{2}$

Step-by-step solution

We have

\frac{\mathrm{U}_{\mathrm{E}}}{\mathrm{U}_{\mathrm{T}}}=\frac{\mathrm{U}_{\mathrm{E}}}{\mathrm{U}_{\mathrm{E}}+\mathrm{U}_{\mathrm{B}}}=\frac{\mathrm{U}_{\mathrm{E}}}{2 \mathrm{U}_{\mathrm{E}}}=\frac{1}{2}

\left[\because \mathrm{U}_{\mathrm{E}}=\mathrm{U}_{\mathrm{B}}=\frac{1}{2} \in_0 \mathrm{E}_0^2=\frac{\mathrm{B}_0^2}{2 \mu_0}\right]

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