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BITSAT2023PhysicsGravitationActual

Two identical particles each of mass ' m ' go round a circle of radius a under the action of their mutual gravitational attraction. The angular speed of each particle will be:

Options

  1. AG m 2 a^3
  2. BGm 8 a ^3
  3. CG m 4 a^3
  4. DG m a^3

Correct answer

C. G m 4 a^3

Step-by-step solution

Radius of circle, r = a Centrifugal force, F=m ^2 r aligned & Gmm (2 a )^2 = m ^2 a & ( F = G M M ₂ ~d ) aligned Here M₁=m ; M₂=m and d=2 a angular speed, = G m 4 a^3

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