The average translational kinetic energy of O_ 2 (molar mass 32)...

Given, ($\mathrm{E}_{\mathrm{O}_{2}}=$0.048 $\mathrm{eV}$) We know that, Translational kinetic energy, ($\mathrm{E}=\frac{3}{2} \mathrm{KT}$) where, ($\mathrm{k}=$) Boltzmann constant ($\mathrm{T}=$) Temperature (\therefore $\mathrm{E} \propto \mathrm{T}$) Since, the temperature is same for both oxygen and nitrogen therefore, ($\mathrm{E}_{\mathrm{O}_{2}}=\mathrm{E}_{\mathrm{N}_{2}}$) (\therefore $\mathrm{E}_{\mathrm{N}_{2}}=$0.048 $\mathrm{eV}$)