The average translational kinetic energy of O ₂ (molar mass 32) molecules at a particular temperature is 0.048 eV . The translational kinetic energy of N ₂ (molar mass 28 ) molecules in eV at the same temperature is

Step-by-step solution

Given, ( E _ O ₂ =0.048 eV ) We know that, Translational kinetic energy, ( E = 3 2 KT ) where, ( k = ) Boltzmann constant ( T = ) Temperature ( E T ) Since, the temperature is same for both oxygen and nitrogen therefore, ( E _ O ₂ = E _ N ₂ ) ( E _ N ₂ =0.048 eV )