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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Physics
Chapter
Mathematics in Physics

BITSAT 2011 · Physics · Mathematics in Physics

The two vectors A and B are drawn from a common point and C = A + B...

The two vectors A→\overrightarrow{\mathrm{A}} and B→\overrightarrow{\mathrm{B}} are drawn from a common point and C→=A→+B→,\overrightarrow{\mathrm{C}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}, then angle between A→\overrightarrow{\mathrm{A}} and B→\overrightarrow{\mathrm{B}} is - (1) 90∘90^{{}^{\circ}} if C2=A2+B2\mathrm{C}^{2}=\mathrm{A}^{2}+\mathrm{B}^{2} (2) greater than 90∘90^{{}^{\circ}} if C2<A2+B2\mathrm{C}^{2}< \mathrm{A}^{2}+\mathrm{B}^{2} (3) greater than 90∘90^{{}^{\circ}} if C2>A2+B2\mathrm{C}^{2} > \mathrm{A}^{2}+\mathrm{B}^{2} (4) less than 90∘90^{{}^{\circ}} if C2>A2+B2\mathrm{C}^{2} > \mathrm{A}^{2}+\mathrm{B}^{2} Correct options are -

Options

  1. A1,2
  2. B1,2,3,4
  3. C2,3,4
  4. D1,2,4

Correct answer

D. 1,2,4

Step-by-step solution

No Solution available
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