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BITSAT 2009

Exam: BITSAT
Year: 2009
Subject: Physics
Chapter: Mathematics in Physics

BITSAT 2009 · Physics · Mathematics in Physics

Given that A + B = R and A^ 2 +B^ 2 =R^ 2 . The angle between A and...

Given that

\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}=\overrightarrow{\mathrm{R}}

and

\mathrm{A}^{2}+\mathrm{B}^{2}=\mathrm{R}^{2}

. The angle between

\overrightarrow{\mathrm{A}}

and

\overrightarrow{\mathrm{B}}

is

Options

A0
B $\pi / 4$
C $\pi / 2$
D $\pi$

Correct answer

C. $\pi / 2$

Step-by-step solution

\cos \theta=\frac{\mathrm{R}^{2}-\mathrm{A}^{2}-\mathrm{B}^{2}}{2 \mathrm{ A} \mathrm{ B}}=\frac{\mathrm{R}^{2}-\mathrm{R}^{2}}{2 \mathrm{AB}}=0\therefore \theta=\pi / 2

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