The distance travelled by a particle starting from rest and moving with an acceleration 4 3 ~ms ⁻² , in the third second is:

Step-by-step solution

Distance travelled in the nth second is given by t _ n = u + a 2 (2 n -1) put u =0, a = 4 3 ~ms ⁻², n =3 d=0+ 4 3 2 (2 3-1)= 4 6 5= 10 3 m