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BITSAT2018PhysicsMotion in One DimensionActual

A ball is dropped vertically from a height d above the ground. It hits the ground and bounces up vertically to a height d / 2 . Neglecting subsequent motion and air resistance, its velocity v varies with height h above the ground as

Correct answer

0

Step-by-step solution

For the uniformly accelerated/decelcrated motion, v 2 = u 2 ± 2 g h So. from this equation. we can say v - h paragraph is parabola. Initially, velocity is downwards ( - v e ) after collision, it reverses the direction with smaller magnitude and velocity is upwards ( - v e ) . So. graph (a) satisfies these conditions. Also, When t = 0 ,   h = d Velocity increases downwards ( U → A ) When t - 1 velocity reverses its direction A ' → B

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