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BITSAT2013PhysicsMotion in One DimensionActual

A man runs at a speed of 4 ~m / s to overtake a standing bus. When he is 6 ~m behind the door at t =0, the bus moves forward and continuous with a constant acceleration of 1.2 ~m / s ² . The man reaches the door in time t . Then,

Options

  1. A4 t =6+0.6 t ²
  2. B1.2 t ²=4 t
  3. C4 t²=1.2 t
  4. D6+4 t =0.2 t ²

Correct answer

A. 4 t =6+0.6 t ²

Step-by-step solution

Let us draw the figure for given situation, 4 t =6+ 1 2 1.2 t ² 4 t =6+0.6 t ²

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