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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Nuclear Physics

BITSAT 2024 · Paper 2 · Physics · Nuclear Physics

The atomic mass of _6 C^ 12 is 12.000000 u and that of _6 C^ 13 is...

The atomic mass of 6C12{ }_6 \mathrm{C}^{12} is 12.000000 u and that of 6C13{ }_6 \mathrm{C}^{13} is 13.003354 u. The required energy to remove a neutron from 6C13{ }_6 \mathrm{C}^{13}, if mass of neutron is 1.008665 u , will be:

Options

  1. A62.5 MeV
  2. B6.25 MeV
  3. C4.95 MeV
  4. D49.5 MeV

Correct answer

C. 4.95 MeV

Step-by-step solution

6C13+{ }_6 \mathrm{C}^{13}+ Energy →6C12+0n1\rightarrow{ }_6 \mathrm{C}^{12}+{ }_0 \mathrm{n}^1 Mass defect, Δm=(12.000000+1.008665)−13.003354\Delta \mathrm{m}=(12.000000+1.008665)- 13.003354=-0.00531 u\mathrm{u}\thereforeEnergyrequiredEnergyrequired=\Delta m×931.5=0.00531×931.5MeV=4.95MeV\mathrm{m} \times 931.5=0.00531 \times 931.5\mathrm{MeV}=4.95 \mathrm{MeV}
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