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BITSAT 2022
Exam
BITSAT
Year
2022
Subject
Physics
Chapter
Ray Optics

BITSAT 2022 · Physics · Ray Optics

A mosquito O is sitting infront of a glass rod having spherical end...

A mosquito OO is sitting infront of a glass rod having spherical end of radius of curvature 40cm40 \mathrm{ cm}. The image would be formed at A mosquito O is sitting infront of a glass rod having spherical end of radius of curvature 40 cm . The image would be

Options

  1. A40cm40 \mathrm{ cm} left
  2. Binfinity
  3. C20cm20 \mathrm{ cm} to the right
  4. D15cm15 \mathrm{ cm} to the left

Correct answer

A. 40cm40 \mathrm{ cm} left

Step-by-step solution

As, we know, μ2v−μ1u=μ2−μ1R\frac{\mu_2}{v}-\frac{\mu_1}{u}=\frac{\mu_2-\mu_1}{R}⇒1.5v−1(−20)=1.5−1+40v=−40cm\begin{aligned}& \Rightarrow \quad \frac{1.5}{v}-\frac{1}{(-20)}=\frac{1.5-1}{+40}\\ & v=-40 \mathrm{ cm}\\ & \end{aligned}$Negative sign shows that image is obtained on the same side of object i.e., towards left.
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