BITSAT2011PhysicsRotational MotionActual
A constant torque of 31.4 ~N - m is exerted on a pivoted wheel. If angular acceleration of wheel is 4 rad / s ², then the moment of inertia of the wheel is
Options
- A2.5 ~kg ~m ²
- B3.5 ~kg ~m ²
- C4.5 ~kg ~m ²
- D5.5 ~kg ~m ²
Correct answer
A. 2.5 ~kg ~m ²
Step-by-step solution
I= = 31.4 4 = 31.4 4 3.14 =2.5 ~kg ~m ² .