In the circuit shown assume the diode to be ideal. When V_i increases from -2 V to 6 V , the change in current is (in mA)

Correct answer: B. 20 l_ initial =0 for V_i ≤+1 ~V This diode conduct only beyond V_i=+1 ~V I_ final = (5)/(250)= 0.02 ~A So, change in I=0.02 ~A=20 ~mA

BITSAT 2022

Exam: BITSAT
Year: 2022
Subject: Physics
Chapter: Semiconductors

BITSAT 2022 · Physics · Semiconductors

In the circuit shown assume the diode to be ideal. When V_i...

In the circuit shown assume the diode to be ideal. When

V_i

increases from

-2 \mathrm{ V}

6 \mathrm{ V}

, the change in current is (in

\mathrm{mA})

Options

AZero
B $20$
C $\frac{25}{8}$
D $32$

Correct answer

B. $20$

Step-by-step solution

l_{

\text{initial }

}=0

\text{ for }

V_i \leq+1

\mathrm{~V}

This diode conduct only beyond

V_i=+1 \mathrm{~V}

I_{

\text{final }

\frac{5}{250}=

0.02

\mathrm{~A}

So, change in

I=0.02 \mathrm{~A}=20 \mathrm{~mA}

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