By Newton's law of cooling,
tθ1−θ2=−k[2θ1+θ2−θ0]....(1)Aspherecoolsfrom62∘Cto50∘Cin10min.1062−50=−k[262+50−θ0]....(2)Now,spherecoolsfrom50∘Cto42∘Cinnext10min.1050−42=−k[250+42−θ0]....(3)Dividingeqn .(2)by(3)weget,46−θ056−θ0=0.81.2or0.4θ0=10.4
Hence \theta_{0}=26^{{}^{\circ}}
C