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BITSAT 2009
Exam
BITSAT
Year
2009
Subject
Physics
Chapter
Thermal Properties of Matter

BITSAT 2009 · Physics · Thermal Properties of Matter

A body of length 1 m having cross-sectional area 0.75 m^ 2 has heat...

A body of length 1m1 \mathrm{ m} having cross-sectional area 0.75m20.75 \mathrm{ m}^{2} has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if K=200Jm−1K−1\mathrm{K}=200 \mathrm{Jm}^{-1} \mathrm{ K}^{-1}

Options

  1. A20∘C20^{{}^{\circ}} \mathrm{C}
  2. B40∘C40^{{}^{\circ}} \mathrm{C}
  3. C80∘C80^{{}^{\circ}} \mathrm{C}
  4. D100∘C100^{{}^{\circ}} \mathrm{C}

Correct answer

B. 40∘C40^{{}^{\circ}} \mathrm{C}

Step-by-step solution

Qt=KA⁡Δθℓ⇒6000=200×0.75×Δθ1∴Δθ=6000×1200×0.75=40∘C\frac{Q}{t}=\frac{\operatorname{KA} \Delta \theta}{\ell} \Rightarrow 6000=\frac{200 \times 0.75 \times \Delta \theta}{1}\therefore \Delta \theta=\frac{6000 \times 1}{200 \times 0.75}=40^{{}^{\circ}} \mathrm{C}
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