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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Physics
Chapter
Units and Dimensions

BITSAT 2014 · Physics · Units and Dimensions

For the equation F=A^ a ^ b ^ c , where F is the force, A is the...

For the equation F=Aa\mathrmvb\mathrmdc,\mathrm{F}=\mathrm{A}^{a} \mathrmv^{\mathrm{b}} \mathrmd^{\mathrm{c}}, where F\mathrm{F} is the force, A is the area, vv is the velocity and d is the density, the values of a,ba, b and cc are respectively

Options

  1. A1,2,1
  2. B2,1,1
  3. C1,1,2
  4. D0,1,1

Correct answer

A. 1,2,1

Step-by-step solution

\left[\mathrm{MLT}^{-2}\right]=\left[L2a\mathrm{L}^{2 \mathrm{a}}\right]\times\left[Lb\mathrm{L}^{\mathrm{b}} \mathrm{T}^{-\mathrm{b} }\right] \left[Mc\mathrm{M}^{\mathrm{c}} \mathrm{L}^{-3 \mathrm{c} }\right]=\left[\mathrm{M}^{c\mathrm{c}} \mathrm{L}^{2 \mathrm{a}+\mathrm{b}-$3 $\mathrm{c}$} $\mathrm{T}^{-\mathrm{b}}\right]$ Comparing powers of $\mathrm{M}$, $\mathrm{L}$ and $\mathrm{T}$, on both sides, we get\begin{array}{l} \mathrm{c}=1,2 \mathrm{a}+\mathrm{b}-3 \mathrm{c}=1,- \mathrm{b}=-2 \text{ or } \mathrm{b}=2 \\ \text{ Also, }2 \mathrm{a}+2-3(1)=1 \Rightarrow 2 \mathrm{a}=2 \text{ or } \mathrm{a}=1 \end{array}$∴\therefore This is 1,2,1
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