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Young's double slit experiment is performed in a medium of refractive index of 1.33 . The maximum intensity is I₀ . The intensity at a point on the screen, where path difference between the light coming out from slits is 4 , is

Options

  1. A0
  2. BI₀ 2
  3. C3 I₀ 8
  4. D2 I₀ 3

Correct answer

B. I₀ 2

Step-by-step solution

Given, path difference, x= 4 Phase difference, = ( 2 ) (Path difference) = 2 4 = 2 ...(i) It is given that, maximum intensity is I₀ . So, intensity at a point on the screen, where phase difference is given by aligned I & =I₀ ^2 ( 2 ) & =I₀ ^2 ( / 2 2 ) [ using Eq.(i) ] & =I₀ ( 1 2 )^2 & = I₀ 2 aligned

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