Quantrex Academy Quantrex AcademyPYQs with solutions · JEE · NEET · NDA

Home · BITSAT · Physics · Wave Optics

Wave Optics — BITSAT Physics PYQs

27 previous year questions from Wave Optics with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

27 questionsPhysicsSolutions on every page
1

Young's double slit experiment is performed in a medium of refractive index of 1.33 . The maximum intensity is I₀ . The intensity at a point on the screen, where path difference be

BITSAT 2024 Solution
View →
2

In YDSE, monochromatic light falls on a screen 1.80 m from two slits separated by 2.08 mm . The first and second order bright fringes are separated by 0.553 mm . The wavelength of

BITSAT 2024 Solution
View →
3

A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm . The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from

BITSAT 2024 Solution
View →
4

The property of light which cannot be explained by Huygen's construction of wavefront is

BITSAT 2024 Solution
View →
5

When a light ray incidents on the surface of a medium, the reflected ray is completely polarized. Then the angle between reflected and refracted rays is

BITSAT 2024 Solution
View →
6

A single slit of a width a is illuminated by a monochromatic light of wavelength 600 ~nm . The value of ' a ' for which first minimum appears at =30^ on the screen will be :

BITSAT 2023 Solution
View →
7

The ratio of intensities at two points P and Q on the screen in a Young's double slit experiment where phase difference between two wave of same amplitude are 3 and 2 , respectivel

BITSAT 2023 Solution
View →
8

In a Young's double slit experiment, the intensities at two points, for the path difference 4 and 3 ( being the wavelength of light used) are I₁ and I₂ respectively. If I₀ denotes

BITSAT 2023 Solution
View →
9

In a young's double slit arrangement frings are produced using light of wavelength 4000 Å . One slit is covered by a thin plate of glass of refractive index 1.4 and the other with

BITSAT 2022 Solution
View →
10

Consider the optical system shown in Fig. The point source of light S is having wavelength equal to . The light is reaching screen only after reflection. For point P to besecond ma

BITSAT 2021 Solution
View →
11

A thin sheet of glass ( =1.5) of thickness 6 micron introduced in the path of one of the interfering beams in a double slit experiment shifts the central fringe to a position previ

BITSAT 2020 Solution
View →
12

In Young's double-slit experiment, the distance between slits and screen is 2 m and distance between slits is 0 . 25 mm . A light of wavelength 800 nm is used to find fringes o

BITSAT 2019 Solution
View →
13

Two monochromatic light waves are travelling with same frequency and constant phase difference. If both waves interfere, then

BITSAT 2019 Solution
View →
14

In Young's double slit experiment, intensity at a point is 1 4 of the maximum intensity. Angular position of this point is

BITSAT 2018 Solution
View →
15

In Young's double slit experiment, the slits are 2 mm apart and are illuminated by photons of two wavelengths λ 1 = 12000 Å and λ 2 = 10000 Å . At what mi

BITSAT 2017 Solution
View →
16

The ratio of intensity at the centre of a bright fringe to the intensity at a point distance one-fourth of the distance between two successive bright fringes will be

BITSAT 2017 Solution
View →
17

In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is is K ,( being the wave length of light used). The intensity at a

BITSAT 2016 Solution
View →
18

Calculate the wavelength of light used in an interference experiment from the following data: Fringe width =0.03 ~cm . Distance between the slits and eyepiece through which the int

BITSAT 2015 Solution
View →
19

In a YDSE, the light of wavelength =5000 Ã is used, which emerges in phase from two slits a distance d =3 10⁻⁷ ~m apart. Atransparent sheet of thickness t =1.5 10⁻⁷ ~m refractive i

BITSAT 2015 Solution
View →
20

The angular size of the central maxima due to a single slit diffraction is a slit width )

BITSAT 2014 Solution
View →
21

Find the final intensity of light (I"), if the angle between the axes of two polaroids is 60^ .

BITSAT 2014 Solution
View →
22

In Young's double slit experiment 10 th order maximum is obtained at the point of observation in the interference pattern for =7000 . If the source is replaced by another one of wa

BITSAT 2013 Solution
View →
23

A mica slit of thickness t and refractive index is introduoed in theray from the first source S₁ . By how much distance of fringes pattern will be displaced?

BITSAT 2012 Solution
View →
24

In a Young's double slit experiment the angular width of a fringe formed on a distant screen is 1^ . The wavelength fo the light used is 6280 . What is the distance between the two

BITSAT 2012 Solution
View →
25

If the distance between the first maxima and fifth minima of a double slit pattern is 7 ~mm and the slits are separated by 0.15 ~mm with the screen 50 cm . from the slits, then the

BITSAT 2011 Solution
View →
26

When a mica sheet of thickness 7 microns and =1.6 is placed in the path of one of interfering beams in the biprism experiment then the central fringe gets at the position of sevent

BITSAT 2009 Solution
View →
27

In Young's double slit experiment, if the slit widths are in the ratio 1: 2, the ratio of the intensities at minima and maxima will be

BITSAT 2009 Solution
View →
Practice all Wave Optics questions in the app →