A sound souorce is moving towards stationary listener with (1)/(10) th of the speed of sound. The ratio of apparent to read frequency is

Correct answer: B. ((10)/(9)) v_ s = v 10 ^ =n v v-v_ s ^ n = v (v- v 10 ) =(10)/(9)

BITSAT 2012

Exam: BITSAT
Year: 2012
Subject: Physics
Chapter: Waves and Sound

BITSAT 2012 · Physics · Waves and Sound

A sound souorce is moving towards stationary listener with (1)/(10)...

A sound souorce is moving towards stationary listener with

\frac{1}{10}

th of the speed of sound. The ratio of apparent to read frequency is

Options

A $\left(\frac{9}{10}\right)^{2}$
B $\left(\frac{10}{9}\right)$
C $\left(\frac{11}{10}\right)$
D $\left(\frac{11}{10}\right)^{2}$

Correct answer

B. $\left(\frac{10}{9}\right)$

Step-by-step solution

v_{\mathrm{s}}=\frac{\mathrm{v}}{10} \quad \mathrmn^{\prime}=\mathrm{n} \frac{\mathrm{v}}{\mathrm{v}-\mathrm{v}_{\mathrm{s}}}\frac{\mathrmn^{\prime}}{\mathrm{n}}=\frac{\mathrm{v}}{

\left(\mathrm{v}-\frac{\mathrm{v}}{10}\right)}=\frac{10}{9}

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