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COMEDK2024Evening ShiftChemistryChemical EquilibriumActual

At 700 K , the Equilibrium constant value for the formation of HI from H ₂ and I ₂ is 49.0 . 0.7 mole of HI(g) is present at equilibrium. What will be the concentrations of H ₂ and I ₂ gases if we initially started with HI(g) and allowed the reaction to reach equilibrium at the same temperature?

Options

  1. A0.3442
  2. B0.4692
  3. C0.521
  4. D0.1

Correct answer

D. 0.1

Step-by-step solution

The reaction is: H₂(g) + I₂(g) 2HI(g) K_c = [HI]^2 [H₂][I₂] = 49.0 Since the reaction starts with only HI(g) , it decomposes to give H₂ and I₂ in 1:1 ratio. Let [H₂] = [I₂] = x 49.0 = (0.7)^2 x^2 x^2 = 0.49 49.0 = 0.01 x = 0.1 mol/L

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