For the reaction 2 ~N ₂ O ₅ 4 NO ₂+ O ₂ . If inital pressure is 100 ~atm and rate constant k is 3.38 10⁻⁵ ~s ⁻¹ . After 20 ~min the final pressure of N ₂ O ₅ will be

Step-by-step solution

The reaction 2 N ₂ O ₅ 4 NO ₂ + O ₂ is a first-order reaction. The rate equation for a first-order reaction is given by P_t = P₀ e^ -kt , where P₀ is the initial pressure and P_t is the pressure at time t . Given values are: P₀ = 100 atm k = 3.38 10⁻⁵ s ⁻¹ t = 20 min = 20 60 s = 1200 s Substituting these values into the equation: P_t = 100 e^ -(3.38 10⁻⁵) 1200 Calculate the exponent: -(3.38 10⁻⁵) 1200 = -0.04056 Now calculate P_t : P_t = 100 e^ -0.04056 Using the approximation e^ -x 1 - x for small x : P_t 100 (1 -