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COMEDK20269 May 2026Morning ShiftChemistryChemical KineticsActual

The rate constants for two different reactions, k₁ and k₂ are 10¹⁶ e^ -2000/T and 10¹⁵ e^ -1000/T respectively. The temperature at which k₁ = k₂ is

Options

  1. A2000 2.303 K
  2. B1000 K
  3. C1000 2.303 K
  4. D2000 K

Correct answer

C. 1000 2.303 K

Step-by-step solution

Given k₁ = 10¹⁶ e^ -2000/T and k₂ = 10¹⁵ e^ -1000/T Equating k₁ and k₂ : 10¹⁶ e^ -2000/T = 10¹⁵ e^ -1000/T 10¹⁶ 10¹⁵ = e^ -1000/T e^ -2000/T 10 = e^ 1000/T Taking natural logarithm on both sides: (10) = 1000 T 2.303 ₁₀(10) = 1000 T 2.303 = 1000 T T = 1000 2.303 K Answer: 1000 2.303 K

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