Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK20269 May 2026Morning ShiftChemistryChemical KineticsActual

Identify the correct values to be plotted in the graph, the slope of which can be used to determine the activation energy of a reaction.

Options

  1. Ak T vs T
  2. Bk vs T
  3. Ck vs 1 T
  4. DT k vs 1 T

Correct answer

C. k vs 1 T

Step-by-step solution

According to the Arrhenius equation: k = A e^ -E_a / RT Taking the natural logarithm on both sides: k = A - E_a RT This equation represents a straight line of the form y = mx + c , where y = k and x = 1 T . Plotting k versus 1 T yields a straight line with slope m = - E_a R . Thus, the activation energy E_a can be determined from the slope of this graph. Answer: k vs 1 T

Practice Chemical Kinetics on Quantrex Academy →

More from Chemical Kinetics

When the concentration of the reactant in a given reaction is halved and if the rate of reaction is halved, the order of the reaction is: 2026A first order reaction is 50%complete in 30 minutes at 300 K and in 10 minutes at 320 K. The activation energy of the reaction (E_a ) is: [R=8.314 J K ⁻¹ mol ⁻¹ ; log 2 = 0.3010; l 2026In the synthesis of NH₃ from H₂ and N₂ , if 6 10⁻² mole of hydrogen disappears in 10 minutes, the number of moles of NH₃ formed in 0.3 minutes is: 2026The initial pressure of the system before decomposition for a first order gas phase reaction A_ (g) B_ (g) + C_ (g) was P_i . After lapse of time 't', total pressure of the system 2026Which of the following factors is altered by the addition of a catalyst during a chemical reaction? 2026The rate constants for two different reactions, k₁ and k₂ are 10¹⁶ e^ -2000/T and 10¹⁵ e^ -1000/T respectively. The temperature at which k₁ = k₂ is 202660% of a first order reaction was completed in 60 min, then 50% of the same reaction can be completed in: [log 4 = 0.60, log 5=0.69] 2026Rate law can be determined from a balanced chemical equation if 2026 Full Chemical Kinetics list All COMEDK PYQs