The quantity of Ca that can be produced from molten CaCl₂ , with the same quantity of electricity (in coulombs) required to produce 4.8 g of Mg from molten MgCl₂ is: [Atomic mass of Mg=24 u; Atomic mass of Ca=40 u]

Step-by-step solution

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the masses of the substances deposited are proportional to their equivalent weights. W_ Ca W_ Mg = E_ Ca E_ Mg Equivalent weight of Mg, E_ Mg = 24 2 = 12 Equivalent weight of Ca, E_ Ca = 40 2 = 20 Given W_ Mg = 4.8 g. W_ Ca 4.8 = 20 12 W_ Ca = 20 12 4.8 = 8.0 g Answer: 8.0 g