x moles of K₂ Cr₂ O₇ oxidises 1 mole of ferrous oxalate, in acidic medium. Hence 'x' is:

Step-by-step solution

In acidic medium, potassium dichromate acts as an oxidizing agent and its n-factor is 6 . Cr₂O₇²⁻ + 14H^+ + 6e^- 2Cr³⁺ + 7H₂O Ferrous oxalate ( FeC₂O₄ ) undergoes oxidation where both Fe²⁺ and C₂O₄²⁻ are oxidized. Fe²⁺ Fe³⁺ + e^- C₂O₄²⁻ 2CO₂ + 2e^- Total electrons lost per mole of FeC₂O₄ is 1 + 2 = 3 . Thus, the n-factor of FeC₂O₄ is 3 . Using the law of equivalence: Equivalents of K₂Cr₂O₇ = Equivalents of FeC₂O₄ x 6 = 1 3 x = 3 6 = 0.5 Answer: 0.5