MHT CET202620 April 2026Evening ShiftChemistryRedox ReactionsActual

What is the oxidation state of Xe in XeOF ₄ ?

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Correct answer

D. +6

Step-by-step solution

Let the oxidation state of Xe in XeOF ₄ be x . The oxidation state of oxygen (O) is -2 and that of fluorine (F) is -1 . Since the molecule is neutral, the sum of the oxidation states of all atoms must be zero. x + (-2) + 4(-1) = 0 x - 2 - 4 = 0 x - 6 = 0 x = +6 The oxidation state of Xe in XeOF ₄ is +6 . Answer: +6

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