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COMEDK2019ChemistryRedox Reactions

50 ec of oxalic acid is oxidised by 25 cc of 0.20 ~N KMnO . The mass of oxalic acid present in 500 ce of the solution is

Options

  1. A3.15 ~g
  2. B31.5 ~g
  3. C6.3 ~g
  4. D63 ~g

Correct answer

A. 3.15 ~g

Step-by-step solution

Equivalent moles of oxalic acid = Equivalent moles =N₁ V₁=25 0.2 10⁻³=5 10⁻³=0.005 Weight of oxalic acid Eq. weight of oxalic acid =0.005 Weight of oxalic acid =0.05 63=0.315 ~g 0.315 ~g in 50 ce of oxalic acid. In 500 ce solution, mass of oxalic acid is =0.315 500 50 =3.15 ~g

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