COMEDK2019ChemistryRedox Reactions
50 ec of oxalic acid is oxidised by 25 cc of 0.20 ~N KMnO . The mass of oxalic acid present in 500 ce of the solution is
Options
- A3.15 ~g
- B31.5 ~g
- C6.3 ~g
- D63 ~g
Correct answer
A. 3.15 ~g
Step-by-step solution
Equivalent moles of oxalic acid = Equivalent moles =N₁ V₁=25 0.2 10⁻³=5 10⁻³=0.005 Weight of oxalic acid Eq. weight of oxalic acid =0.005 Weight of oxalic acid =0.05 63=0.315 ~g 0.315 ~g in 50 ce of oxalic acid. In 500 ce solution, mass of oxalic acid is =0.315 500 50 =3.15 ~g